3x^2-x+0,06=0

Solution for 3x^2-x+0,06=0 equation:

3x^2-x+0.06=0

We add all the numbers together, and all the variables

3x^2-1x+0.06=0

a = 3; b = -1; c = +0.06;
Δ = b2-4ac
Δ = -12-4·3·0.06
Δ = 0.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.28}}{2*3}=\frac{1-\sqrt{0.28}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.28}}{2*3}=\frac{1+\sqrt{0.28}}{6}
$